-p^2=-324

Solution for -p^2=-324 equation:

-p^2=-324

We move all terms to the left:

-p^2-(-324)=0

We add all the numbers together, and all the variables

-1p^2+324=0

a = -1; b = 0; c = +324;
Δ = b2-4ac
Δ = 02-4·(-1)·324
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-1}=\frac{-36}{-2}
=+18
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-1}=\frac{36}{-2}
=-18
$